Question

How do you prove `(1+costheta)/sintheta+sintheta/costheta=(costheta+1)/(sinthetacostheta)`?

Answer 1

Please see below.

Explanation:

`(1+costheta)/sintheta+sintheta/costheta`

= `(costheta(1+costheta)+sin^2theta)/(sinthetacostheta)`

= `(costheta+cos^2theta+sin^2theta)/(sinthetacostheta)`

= `(costheta+1)/(sinthetacostheta)`