How do you simplify #81^(-3/2)#?

2 Answers
Sep 19, 2016

#81^(-3/2)=1/729#

Explanation:

#81^(-3/2)#

= #(3^4)^(-3/2)#

= #3^((4xx-3/2))#

= #3^(2xx-3)#

= #3^(-6)#

= #1/3^6#

= #1/729#

Sep 19, 2016

#1/729#

Explanation:

Recall: 2 laws of indices #" " rarr " "x^-m = 1/x^m#

#color(white)(xxxxxxxxxxxxxxxxx) rarr" " x^(p/q) = rootq (x^p) = (rootq x)^p#

#81^(-3/2) = 1/(sqrt81^3)" "larr# the cube of the square root of 81

=#1/(9^3)#

=#1/729#

Note that 81 is both a square number and a 4th power.
However, the square root can be obtained immediately.

In work on indices, usually only the principal (+) square root is considered.