Question

How do you solve `-3=(37-3n)^(1/2)-n`?

Answer 1

n = 7, - 4

Explanation:

-3 = `(37 - 3n)^(1/2) -n`
or, -3 + n = `(37 - 3n)^(1/2)` [squaring both sides]
or, `(-3 + n)^2 = (37 - 3n)^[(1/2)*2]`
or, 9 - 6n + `n^2` = 37 - 3n
or, `n^2 - 3n - 28 = 0`
or, `n^2 -7n + 4n - 28 = 0`
or, n ( n - 7 ) + 4 ( n - 7 ) = 0
or, (n - 7) (n + 4 ) = 0
or, n = 7, - 4