Question #6c321

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Answer 1 · 2016-09-21T20:51:49

#{-25, -23}#

Any odd integer can be represented as #2n+1#, where #n# is an integer. Suppose #2n+1# is the lesser of the consecutive odd integers, then we have

#-48 = (2n+1) + (2n+1)+2#

#=4n+4#

#=4(n+1)#

#=> n+1 = -48/4 = -12#

#=> n = -13#

Thus, substituting in, we have the consecutive odd integers as

#2n+1 = 2(-13)+1 = -25#
and
#(2n+1)+2 = -25+2 = -23#

Checking, #-25 + -23 = -48#, as desired.