How do you simplify #(2-4i)(-6+4i)#?

1 Answer
Alan P.
Sep 22, 2016

#(2-4i)(-6+4i)=color(brown)(4+32i)#

Explanation:

#(color(red)(2)-color(red)(4i))(color(blue)(-6+4i))#

#color(white)("XXX")=color(red)(2)(color(blue)(-6+4i) ) - color(red)(4i)(color(blue)(-6+4i))#

#color(white)("XXX")=color(magenta)(-12+8i)-(color(green)(-24i+16i^2))#

#color(white)("XXX")=color(magenta)(-12)-(color(green)(-16))+color(magenta)(8i)+color(green)(24i)#

#color(white)("XXX")=4+32i#

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