How do you solve the quadratic using the quadratic formula given #x^2=-3x+40#?

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Answer 1 · 2016-09-23T10:56:10

#x = - 8, 5#

We have: #x^(2) = - 3 x + 40#

#=> x^(2) + 3 x - 40 = 0#

#=> x = (- 3 pm sqrt(3^(2) - 4 (1) (- 40))) / (2 (1))#

#=> x = (- 3 pm sqrt(169)) / (2)#

#=> x = (- 3 pm 13) / (2)#

#=> x = - 8, 5#

Therefore, the solutions to the equation are #x = - 8# and #x = 5#.