Question

Question #b9b46

Answer 1

`"9.69 mL"`

Explanation:

The problem provides you with the density of the helium sample, which essentially means that it is providing you with the mass of one unit of volume of helium at a certain temperature.

A density of `"0.17847 g/L"` means that at a specific temperature, `"1 L"` of helium has a mass of `"0.17847 g"`.

In your case, the sample is said to have a mass of `1.73 * 10^(-3)"g"`. Use the given density to find the volume of the sample in liters

`1.73 * 10^(-3)color(red)(cancel(color(black)("g"))) * "1 L"/(0.17847 color(red)(cancel(color(black)("g")))) = 9.694 * 10^(-3)"L"`

Now all you have to do is convert the volume from liters to milliliters

`9.694 * color(blue)(cancel(color(black)(10^(-3)))) color(red)(cancel(color(black)("L")))* (color(blue)(cancel(color(black)(10^(3))))"mL")/(1color(red)(cancel(color(black)("L")))) = color(green)(bar(ul(|color(white)(a/a)color(black)("9.69 mL")color(white)(a/a)|)))`

The answer is rounded to three sig figs, the number of sig figs you have for the mass of the sample.