How do you expand #(y-3x^2)^2#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer S.S Sep 27, 2016 #(y - 3x^2)^2 = (y - 3x^2) (y - 3x^2)# This expands to #y^2 -3xy^2 -3xy^2 + 9x^4# Which is equal to #y^2 -6xy^2 + 9x^4# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 1415 views around the world You can reuse this answer Creative Commons License