Question

How do you find `(dy)/(dx)` given `y^2+3x=2`?

Answer 1

`(dy)/(dx)=-3/(2sqrt(2-3x))`

Explanation:

As `y^2+3x=2`, we have

`y^2=2-3x` and `y=sqrt(2-3x)`

and using chain rule

`(dy)/(dx)=1/(2sqrt(2-3x))xx(-3)`

= `-3/(2sqrt(2-3x))`