Question

If I inhale 2.20 L of gas at a temperature of 18°C at a pressure of 1.50 atm, how many moles of gas were inhaled?

Answer 1

`n="0.138 mol"`

Explanation:

You will need the ideal gas law to answer this question. The formula for the ideal gas law is:

Known
`P="1.50 atm"`
`V="2.20 L"`
`R="0.082057338 L atm K"^(-1) "mol"^(-1)"`
`T="18"^@"C"+"273.15 K=291 K"`

Unknown
`n`

Solution
Rearrange the formula to isolate `n`. Substitute the known values into the formula and solve.

`n=(PV)/(RT)`

`n=(1.50cancel"atm"xx2.20cancel"L")/(0.082057338cancel"L" cancel"atm" cancel"K"^(-1) "mol"^(-1)xx291cancel"K")="0.138 mol"`