Question

How do you factor `16x^2+8x-3`?

Answer 1

`(4x-1)(4x+3)`

Explanation:

If you cannot do this by inspection.
Then use the formula.
The solution to `y=ax^2+bx+c` is `y=(-b+-sqrt(b^2-4ac))/(2a)`

So`y=(-8+-sqrt(64-4.16.-3))/32`

Or `y=(-8+16)/32`or `(-8-16)/32`
Or `y=8/32` or`-24/32`

Or `y=1/4 or -3/4`

This gives the factorisation.....