Question

A circle has a center at `(1 ,3 )` and passes through `(2 ,4 )`. What is the length of an arc covering `pi /4` radians on the circle?

Answer 1

`s = (sqrt2pi)/4`

Explanation:

Compute the radius:

`r² = (2 - 1)² + (4 - 3)²`

`r = sqrt(2)`

The arc length ,s, is:

`s = rtheta`

`s = (sqrt2pi)/4`