If y=sin^5x then what is dy/dx? Calculus Differentiating Trigonometric Functions Intuitive Approach to the derivative of y=sin(x) 1 Answer Steve M Oct 4, 2016 Use the chain rule Explanation: If y=sin^5x, then Let u=sin x, Then (du)/(dx)=cosx and y=u^5 so (dy)/(du)=5u^4 Chain rule gives (dy)/(dx)=(dy)/(du) (du)/(dx). so: (dy)/(dx)= 5u^4 cosx = 5sin^4x cos x Answer link Related questions What is the derivative of -sin(x)? What is the derivative of sin(2x)? How do I find the derivative of y=sin(2x) - 2sin(x)? How do you find the second derivative of y=2sin3x-5sin6x? How do you compute d/dx 3sinh(3/x)? How do you find the derivative y=xsinx + cosx? What is the derivative of sin(x^2y^2)? What is f'(-pi/3) when you are given f(x)=sin^7(x)? How do you find the fist and second derivative of pi*sin(pix)? If f(x)= 2x sin(x) cos(x), how do you find f'(x)? See all questions in Intuitive Approach to the derivative of y=sin(x) Impact of this question 13777 views around the world You can reuse this answer Creative Commons License