Question

A triangle has sides A, B, and C. Sides A and B are of lengths `5` and `1`, respectively, and the angle between A and B is `(11pi)/12`. What is the length of side C?

Answer 1

Length of side C is `5.97(2dp) unit`

Explanation:

The sides A,B and their included angle are `A=5;B=1; /_c=11*180/12=165^0`
Applying cosine law , `C^2=A^2+b^2-2*A*B*cosc` we get `C= sqrt(5^2+1^2-2*5*1*cos165) = sqrt(35.66)=5.97(2dp) unit`[Ans]