Question

How do you solve `2cosx+3=0` in the interval `0<=x<=2pi`?

Answer 1

No solution

Explanation:

As `2cosx+3=0`, we have

`2cosx=-3` or

`cosx=-3/2`

But `cosx` ranges only from `-1` to `1` only and cannot take the value `-3/2`.

Hence, there is no solution.