How do you multiply (7i)(6i)(-3-5i)? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Henry W. Oct 8, 2016 126+210i Explanation: Multiplying 7i*6i we get 42i^2=-42 (recall that i^2=-1) Now multiply -42(-3-5i), which equals 126+210i Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square (1+i)? What is the geometric interpretation of multiplying two complex numbers? What is the product of 3+2i and 1+7i? How do I use DeMoivre's theorem to solve z^3-1=0? How do I find the product of two imaginary numbers? How do you simplify (2+4i)(2-4i)? How do you multiply (-2-8i)(6+7i)? See all questions in Multiplication of Complex Numbers Impact of this question 2758 views around the world You can reuse this answer Creative Commons License