Question

If a projectile is shot at an angle of `(pi)/8` and at a velocity of `13 m/s`, when will it reach its maximum height?

Answer 1

`t=(24.70)/(19.62)=1.26 " "s`

Explanation:

`t=(v_i^2*sin^2 alpha)/(2*g)=(v_y)^2/(2g)`

`v_y=v_i*sin alpha=13*sin (pi/8)=4.97`

`t=(4.97)^2/(2*9.81)`

`t=(24.70)/(19.62)=1.26 " "s`