How do you simplify #(5+i)(8+i)# and write the complex number in standard form?

1 Answer
Oct 13, 2016

#39+13i#

Explanation:

#color(blue)((5+i))color(brown)((8+i))#

Multiply everything in the RHS brackets by everything in the LHS brackets.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)(
color(brown)(
#[color(blue)(5xx)color(brown)(8)]+[color(blue)(5xx)color(brown)(i)]" "+" "[color(blue)(ixx)color(brown)(8)]+[color(blue)(ixx)color(brown)(i)]#

#40+5i+8i+(-1)#

#39+13i#