Question

How do you solve `secxcscx=2cscx`?

Answer 1

General solution is `x=2npi+-pi/3`, where `n` is an integer.

Explanation:

`secxcscx=2cscx`

Hence, considering `cscx!=0`, `secx=2`

and so `x=+-pi/3` - note that `csc(+-pi/3)!=0`

and as all trigonometric functions are cyclic over `2pi`,

General solution is `x=2npi+-pi/3`, where `n` is an integer.