Question

How do you write the hyperbola `x^2/9-4y^2/9=9` in standard form?

Answer 1

The equation is `x^2/9^2-y^2/(9/2)^2=1`

Explanation:

The standard form is `x^2/a^2-y^2/b^2=1`
so we must reduce the above equation to this form
Dividing by 9, we get
`x^2/(9*9)-y^2/(81/4)=1`
Rewriting the equation
`x^2/9^2-y^2/(9/2)^2=1`
Where `a=9` and `b=9/2`