If a projectile is shot at an angle of #pi/2# and at a velocity of #22 m/s#, when will it reach its maximum height??

1 Answer
Oct 22, 2016

I got: #2.2s#

Explanation:

If I interpreted it right, the bullet is shot perfectly vertically and will reach its maximum height where its final velocity #v_f# will be zero.
We can use kinematics in the form of the relationship:
#v_f=v_i+at#
where the acceleration #a# will be acceleration of gravity #g=9.8m/s^2# directed downwards (and so it will have a negative sign).
We get:
#0=22-9.8t#
rearranging:
#t=22/9.8=2.2s#