How do you write the equation of a line which passes through (0, -3) and has a slope of -5?

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Answer 1 · 2016-10-23T02:19:37

#y=-5x-3#

When given a set of points and the slope, use the point slope formula, which is:

#y-y_1=m(x-x_1)#

Where #y_1# is the #y# in the set of points
#x_1# is the #x# in the set of points
And #m# is the slope

Plug in the numbers into the equation

#y+3=-5(x-0)#

Distribute the #-5# throughout the set of parenthesis

#y+3=-5x+0

Subtract #3# on both sides of the equation

#y=-5x-3#