How do you write an equation of the line parallel to #x+2y=6 through (8,3)?

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Answer 1 · 2016-10-29T13:10:48

#y=-1/2x+19/2#

To write an equation of a straight line we have to determine its slope and a point it passes through.

Two straight lines are parallel if and only if they have same slope.

#x+2y=6#

#rArr2y=6-x#

#rArry=3-x/2#

The slope ight line is of the given strais #-1/2#
Because the two lines are parallel then they have same slope #-1/2#

Equation of a line passing through#(8,3)#and slope #-1/2#

#y-8=-1/2(x-3)#

#y=-1/2x+3/2+8#

#y=-1/2x+19/2#