Question

How do you find the vertex, the focus, and the directrix of the parabola `y^2=4x`?

Answer 1

The vertex is `(0,0)`
The focus `(1,0)`
The directrix is `x=-1`

Explanation:

The vertex is at `(0,0)`
The equation is of the type `y^2=2px`
And `p=2`
So the focus is at `(p/2,0)=(1,0)`
The directrix is `x=-p/2` `=>` `x=-1`
graph{y^2=4x [-10, 10, -5, 5]}