Question

An object with a mass of `5 kg` is on a surface with a kinetic friction coefficient of `4`. How much force is necessary to accelerate the object horizontally at `12 m/s^2`?

Answer 1

Force F=64Newtons.

Explanation:

This case is taken as Motion of block on a rough fixed horizontal surface.
In this case, if the block slides or moves with an acceleration under the influence of an external force 'F', the acceleration of the block is
`a=(F-f_"k")//m`
`=> F = ma + f_"k"`
Now substituting the values we get
F = (5)(12) + 4
`:. F = 64N`