Question

How do you calculate the energy absorbed when `2.0x10^3g` of ice (`CO_2`) sublimate at the normal dry sublimation point? The enthalpy of sublimation 196.3J/g.

Answer 1

We want the energy required for the transition:

`CO_2(s) + Delta rarr CO_2(g)`

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

`2xx10^3*cancelgxx196.3*J*cancel(g^-1)` to get an answer in `"Joules"` as required.

What would be the energy change for the reverse transition:

`CO_2(g) + rarr CO_2(s)`?