Question

How do you solve `log_2 (3x)+log_2 5=log_2 30`?

Answer 1

`x = 2`

Explanation:

`log_2(3x) + log_2(5)`

= `log_2(3x*5)`

= `log_2(15x)`

= `log_2(30)`

Therefore,

`15x=30`

or `x=2`