Question

How do you find the amplitude and period of `y=4sin(144pit)`?

Answer 1

4 and 1/72

Explanation:

The amplitude and period for y= a sin (kt) are a and `2/kpi`.

Here, `a = 4 and k = 144pi`, and so, the period

`P =(2pi)/(144pi)=1/72`.

See how it works.

`y(t+1/72)=4sin(144pi(t+1/72))=4sin(144pit+2pi)=4sin(144pit)=y(t).`

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