Question

How do you write the equation in slope-intercept form of the line that is parallel to y=5x+6 but goes through the point (2,-3)?

Answer 1

Please see the explanation for how I obtained the equation: `y = 5x - 13`

Explanation:

Substitute 2 for x, -3 for y, and 5 for m into the slope-intercept form, `y = mx + b`:

`-3 = 5(2) + b`

Solve for b:

`b = -13`

The equation is:

`y = 5x - 13`