How do you find the x and y intercepts for #x-2y=4#?

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Answer 1 · 2016-11-13T11:15:22

Intercepts are #(0, -2)# and #(4, 0)#

Given:

#x - 2y = 4#

The intercept with the #x# axis can be found by setting #y = 0# - effectively "covering up" the #-2y# term - to get:

#x = 4#

hence the #x# intercept is at #(4, 0)#

The intercept with the #y# axis can be found by setting #x = 0# or covering up the #x# term to get:

#-2y = 4#

Then dividing both sides by #-2# we find:

#y = -2#

So the #y# intercept is at #(0, -2)#

graph{(x-2y-4)((x-4)^2+y^2-0.01)(x^2+(y+2)^2-0.01) = 0 [-8.29, 11.71, -5.08, 4.92]}