Question

How do you factor fully, if possible `21c^4d^3-28c^2d^5+7cd^3`?

Answer 1

`7cd^3(3c^3 - 4cd^2 + 1)`

Explanation:

You find the lowest form of each constant and variable which is present in each term and factor it out. In this case it would be `7`, `c^1 = c` and `d^3` giving:

`7cd^3(3c^(4-1)d^(3-3) - 4c^(2 - 1)d^(5-3) + 1c^(1-1)d^(3-3))`

`7cd^3(3c^3d^0 - 4cd^2 + 1c^0d^0)`

`7cd^3(3c^3 - 4cd^2 + 1)`