How do you solve #\sqrt { x - 4} + 8= 9#?

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Answer 1 · 2016-11-15T03:53:09

#x=5#

#sqrt(x-4) +8 =9#

Subtract #8# from both sides, to isolate the radical.

#sqrt (x-4)= 1#

Square both sides to get rid of the radical.

#x-4 = 1#

Add #4# to both sides to isolate #x#.

#x= 5#

To check, if you plug #5=x#, the equation is proven equal.

#sqrt (5-4) +8 = 9#

#9 = 9 -># Yes!

Hope that helped!