How do you factor #3d^2+23d+14# completely? Algebra Polynomials and Factoring Factoring Completely 1 Answer Suren Abreu Nov 15, 2016 #d=-2/3# and #d=-7# Explanation: #3d^2+23d+14=0# #3d^2+21d+2d+14=0# #3d(d+7)+2(d+7)=0# #(3d+2)(d+7)=0# #3d+2=0# and #d+7=0# #d=-2/3# and #d=-7# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1238 views around the world You can reuse this answer Creative Commons License