Question

Question #40306

Answer 1

The mass of the man `=76kg`
The downward gravitational force on him
`=76xxgN=76xx9.8N=744.8N`

The mass of the Parachute `=5.5kg`
The downward gravitational force on it
`=5.5xxgN=5.5xx9.8N=53.9N`

So total downward gravitational pull
`F_gdarr = (744.8+ 53.9)N = 798.7N`

The net downward acceleration on the system is `2.6ms^-2`

So the net downward force

`F_ndarr=(76+5.5)xx2.6=211.9N`

Now

`F_ndarr=F_gdarr-F_"air"uarr`

`=>F_"air"uarr=F_gdarr-F_ndarr`

`=>F_"air"uarr=798.7-211.9=586.8N`

(a) The upward force exerted on the open parachute by the air`=F_"air"uarr=586.8N`

(b) The downward force exerted by the person on the parachute `=744.8N`