Question

A `9.7"kg"` mass is positioned on top of a vertical spring. What is the upward force exerted on the mass by the spring?

Answer 1

`F_(sp)=85N`

Explanation:

Use Newton's second law, which (in summary) states that `F=ma`. Assuming no friction and that the mass is given in kilograms,

`F_(sp)=9.7kg*8.8m/s^2`

`F_(sp)=85N`

Answer 2

Net downward force on the 9.7 kg mass `F_n= 9.7xx8.8N`

Gravitational force on the 9.7 kg mass `F_g= 9.7xx9.8N`

If the upward force exerted by spring be `F_s` then

`F_n=F_g-F_s`

`=>F_s=F_g-F_n=9.7xx9.8-9.7xx8.8=9.7N`