How do you solve $12 x + 20 > 140$ $12x + 20> 140$ ?

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Answer 1 · 2016-11-20T21:41:52

$x > 10$ $x>10$

$12 x + 20 > 140$ $12x+20>140$

Subtract $20$ $20$ from both sides.

$12 x > 140 - 20$ $12x>140-20$

$12 x > 120$ $12x>120$

Divide both sides by $12$ $12$ .

$x > \frac{120}{12}$ $x>120/12$

$x > 10$ $x>10$

How do you solve 12x+20>14012x + 20> 140?