Question

A parallelogram has sides A, B, C, and D. Sides A and B have a length of `6` and sides C and D have a length of `3`. If the angle between sides A and C is `(7 pi)/12`, what is the area of the parallelogram?

Answer 1

Area of the parallelogram is `17.39(2dp)` sq.unit

Explanation:

We know the area of the parallelogram as `A_p=s_1*s_2*sin theta.`
Here `s_1=6 ; s_2=3; theta= (7*180)/12=105^0 or (180-105)=75^0`
Therefore, Area `A_p= 6*3*sin75=17.39 (2dp)`

Area of the parallelogram is `17.39(2dp)` sq.unit [Ans]