If the angle $\frac{29 π}{6}$ $(29pi)/6$ is in standard position, which quadrant does it terminate?

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If the angle $\frac{29 π}{6}$ $(29pi)/6$ is in standard position, which quadrant does it terminate?

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Answer 1 · 2016-11-26T17:03:05

This angle ends in the second quadrant. See explanation.

Explanation:

First we have to change the fraction in the angle to a mixed number:

$\frac{29 π}{6} = 4 \frac{5}{6} π = 4 π + \frac{5 π}{6}$ $(29pi)/6=4 5/6pi=4pi+(5pi)/6$

Adding a multiple of $2 π$ $2pi$ does not change the end quadrant, so $\frac{29 π}{6}$ $(29pi)/6$ lies in the same quadrant as $\frac{5 π}{6}$ $(5pi)/6$

$\frac{π}{2} \leq \frac{5 π}{6} \leq π$ $pi/2 <= (5pi)/6 <=pi$ , so this angle lies in the second quadrant.

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If the angle $\frac{29 π}{6}$ $(29pi)/6$ is in standard position, which quadrant does it terminate?

1 Answer

Explanation:

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If the angle $\frac{29 π}{6}$ $(29pi)/6$ is in standard position, which quadrant does it terminate?