Question

Question #1d3c4

Answer 1

We know that `cottheta = costheta/sintheta` and `csctheta = 1/sintheta`.

`(sqrt(2)cosx)/sinx - 1/sinx = 0`

`sqrt(2)cosx - 1 = 0`

`cosx= 1/sqrt(2)`

`x = 45˚, 315˚`

Hopefully this helps!