Question

A triangle has sides A, B, and C. Sides A and B are of lengths `7` and `8`, respectively, and the angle between A and B is `(7pi)/12`. What is the length of side C?

Answer 1

Length of side C is `11.92(2dp)` unit

Explanation:

Sides `A=7 ;B=8 ; /_c=(7pi)/12=(7*180)/12=105^0`

Applying Cosine law we get `C^2=(A^2+B^2-2*A*B*cosc) or C^2=(7^2+8^2-2*7*8*cos105)or C=sqrt(7^2+8^2-2*7*8*cos105) =11.92(2dp)`unit [Ans]