Question

How do you solve `3-5y=0`?

Answer 1

`y=3/5`

Explanation:

Leave the 3 where it is and add 5y to both sides of the equation.

`3cancel(-5y)cancel(+5y)=0+5y`

`rArr3=5y`

To solve for y, divide both sides by 5

`3/5=(cancel(5) y)/cancel(5)`

`rArry=3/5" is the solution"`

Answer 2

Add terms to both side and/or multiply both sides by the appropriate factor, until you have an expression of `y`

Explanation:

Start from:

`3-5y=0`

Add `-3` to both sides of the equation:

`3 -5y -3 = -3`

On the left side `3-3=0` so you can simplify these two terms and get:

`-5y=-3`

Now multiply both sides by `-1/5`:

`-5(-1/5)y = -3(-1/5)`

or `y=3/5`