Question

How do you find sin theta = -2/5, with theta in quadrant III?

Answer 1

`t = 204^@58`

Explanation:

`sin t = -2/5 = - 0.4`
Calculator, and trig unit circle -->
sin t = - 0.4 --> `t = - 23^@58` and `t = - 156^@42`
t is in Quadrant III, then the answer is:
`t = - 156^@42`, or `t = 204^@58` (co-terminal)