How do you expand #(10y^3+1)^2#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer anor277 Nov 28, 2016 #(10y^3+1)^2=100y^6+20y^3+1# Explanation: #(10y^3+1)^2=(10y^3+1)(10y^3+1)^2# #=100y^6+10y^3+10y^3+1# #=100y^6+20y^3+1# This follows the old routine of #(a+b)^2=a^2+b^2+2ab#. Here #a=10y^3, b=1#. Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 1378 views around the world You can reuse this answer Creative Commons License