The pressure on a sample of an ideal gas is increased from 715 mmHg to 3.55 atm at constant temperature. If the initial volume of the gas is 485 mL, what is the final volume of the gas?

Question

11159 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-28T21:06:47

The gas is compressed to a volume of #129*mL#.

At constant #T#, #P_1V_1=P_2V_2#; this is Boyle's law.

Now #P_1=(715*mm*Hg)/(760*mm*Hg*atm^-1)=0.941*atm#

#V_2=(P_1V_1)/P_2=(0.941*cancel(atm)xx485*mL)/(3.55*cancel(atm))=129*mL#