Question

How do you calculate the amount of heat (in kJ) required to heat 4.14 kg of water from 21.50 C to 33.85 C.?

Answer 1

You need the specific heat of water, which is widely listed in data books and the public doman.

Explanation:

You need the specific heat of water which is 4.2 `(kJ)/(kg.K)`.

Then you can use the relationship `E = m.c.theta` where `E` is the heat energy involved, `m` is the mass of the substance being heated, and `theta` is the temperature change.

The temperature change here is 4.14 x 4.2 x 12.35 = 214.74 kJ.