Question

How do you solve `Ax=B` given `A=((1, 5))` and `B=(2)`?

Answer 1

Solution is `x=((k),((2-k)/5))`

Explanation:

As `A=((1, 5))` is a `1xx2` matrix and `B=(2)` is a `1xx1` matrix, as `Ax=B`, `x=X`, where `X` is a `2xx1` matrix.

Let `x` be `((x_1),(x_2))`

and hence `Ax=((1, 5))((x_1),(x_2))=(x_1+5x_2)`

But as `Ax=B=(2)`, we have `x_1+5x_2=2`

or `x_2=(2-x_1)/5` and if `x_1=k`

Solution is `x=((k),((2-k)/5))`