How do you write the equation of a line that passes through (4,-3) and has a slope of -3/4?

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Answer 1 · 2016-12-03T15:51:47

#y = -3/4x#

#y = mx + b#

where:
#m =# slope of the line
#b = # y-intercept

the slope is already given (#-3/4#).
All that remains is to find the y-intercept.

To find the y-intercept, we use the coordinates of a point which we know lies on the line. Such a point was also given #(4, -3)#.

#y = -3/4x + b#

#=> -3 = -3/4(4) + b#

#=> -3 = -3 + b#
#=> b = 0#

Since the y-intercept is 0, the equation of the line is

#y = -3/4x#