A solid disk, spinning counter-clockwise, has a mass of #6 kg# and a radius of #2 m#. If a point on the edge of the disk is moving at a rate of #2 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2016-12-04T09:24:03

The angular momentum is #=12kgms^(-1)#
The angular velocity #=1 Hz#

The angular velocity is

#omega=v/r#

where,

#v=2ms^(-1)#

#r=2m#

So,

#omega=2/2=1Hz#

The angular momentum is #L=Iomega#

For a solid disc, #I=(mr^2)/2#

So, #I=6*2^2/2=12kgm^2#

#L=12*1=12kgms^(-1)#