If a gas in a closed container is pressurized from 1.5 atm to 1.6 atm and its original temperature was 298 K, what would be the final temperature of the gas?

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Answer 1 · 2016-12-04T10:45:26

The answer is #=317.9K#

#P_1/T_1=P_2/T_2#

#P_1=1.5 atm#

#P_2=1.6 atm#

#T_1=298K#

#T_2=(P_2T_1)/P_1#

#=(1.6*298)/1.5=317.9K#