A solid disk, spinning counter-clockwise, has a mass of #2 kg# and a radius of #7/4 m#. If a point on the edge of the disk is moving at #7/4 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2016-12-06T07:17:06

The angular momentum is #=49/16kgms^(-1)#
THe angular velocity is #=1Hz#

The angular velocity is

#omega=v/r#

where,

#v=7/4ms^(-1)#

#r=7/4m#

So,

#omega=7/4/7/4=1Hz#

The angular momentum is #L=Iomega#

For a solid disc, #I=(mr^2)/2#

So, #I=2*(7/4)^2/2=49/16kgm^2#

#L=49/16*1=49/16kgms^(-1)#